


In geometry and topology, a channel surface or canal surface is a surface formed as the envelope of a family of spheres whose centers lie on a space curve, its directrix. If the radii of the generating spheres are constant, the canal surface is called a pipe surface. Simple examples are:
- right circular cylinder (pipe surface, directrix is a line, the axis of the cylinder)
- torus (pipe surface, directrix is a circle),
- right circular cone (canal surface, directrix is a line (the axis), radii of the spheres not constant),
- surface of revolution (canal surface, directrix is a line).
Canal surfaces play an essential role in descriptive geometry, because in case of an orthographic projection its contour curve can be drawn as the envelope of circles.
- In technical area canal surfaces can be used for blending surfaces smoothly.
Envelope of a pencil of implicit surfaces
Given the pencil of implicit surfaces
-
Φ
c
:
f
(
x
,
c
)
=
0
,
c
∈
[
c
1
,
c
2
]
{\displaystyle \Phi _{c}:f({\mathbf {x} },c)=0,c\in [c_{1},c_{2}]}
,
two neighboring surfaces
Φ
c
{\displaystyle \Phi _{c}}
and
Φ
c
+
Δ
c
{\displaystyle \Phi _{c+\Delta c}}
intersect in a curve that fulfills the equations
-
f
(
x
,
c
)
=
0
{\displaystyle f({\mathbf {x} },c)=0}
and f ( x , c + Δ c ) = 0 {\displaystyle f({\mathbf {x} },c+\Delta c)=0}
.
For the limit
Δ
c
→
0
{\displaystyle \Delta c\to 0}
one gets
f
c
(
x
,
c
)
=
lim
Δ
c
→
0
f
(
x
,
c
)
−
f
(
x
,
c
+
Δ
c
)
Δ
c
=
0
{\displaystyle f_{c}({\mathbf {x} },c)=\lim _{\Delta c\to \ 0}{\frac {f({\mathbf {x} },c)-f({\mathbf {x} },c+\Delta c)}{\Delta c}}=0}
.
The last equation is the reason for the following definition.
- Let
Φ
c
:
f
(
x
,
c
)
=
0
,
c
∈
[
c
1
,
c
2
]
{\displaystyle \Phi _{c}:f({\mathbf {x} },c)=0,c\in [c_{1},c_{2}]}
be a 1-parameter pencil of regular implicit C 2 {\displaystyle C^{2}}
surfaces ( f {\displaystyle f}
being at least twice continuously differentiable). The surface defined by the two equations
-
f
(
x
,
c
)
=
0
,
f
c
(
x
,
c
)
=
0
{\displaystyle f({\mathbf {x} },c)=0,\quad f_{c}({\mathbf {x} },c)=0}
-
f
(
x
,
c
)
=
0
,
f
c
(
x
,
c
)
=
0
{\displaystyle f({\mathbf {x} },c)=0,\quad f_{c}({\mathbf {x} },c)=0}
is the envelope of the given pencil of surfaces.[1]
Canal surface
Let
Γ
:
x
=
c
(
u
)
=
(
a
(
u
)
,
b
(
u
)
,
c
(
u
)
)
⊤
{\displaystyle \Gamma :{\mathbf {x} }={\mathbf {c} }(u)=(a(u),b(u),c(u))^{\top }}
be a regular space curve and
r
(
t
)
{\displaystyle r(t)}
a
C
1
{\displaystyle C^{1}}
-function with
r
>
0
{\displaystyle r>0}
and
|
r
˙
|
<
‖
c
˙
‖
{\displaystyle |{\dot {r}}|<\|{\dot {\mathbf {c} }}\|}
. The last condition means that the curvature of the curve is less than that of the corresponding sphere.
The envelope of the 1-parameter pencil of spheres
-
f
(
x
;
u
)
:=
‖
x
−
c
(
u
)
‖
2
−
r
2
(
u
)
=
0
{\displaystyle f({\mathbf {x} };u):={\big \|}{\mathbf {x} }-{\mathbf {c} }(u){\big \|}^{2}-r^{2}(u)=0}
is called a canal surface and
Γ
{\displaystyle \Gamma }
its directrix. If the radii are constant, it is called a pipe surface.
Parametric representation of a canal surface
The envelope condition
-
f
u
(
x
,
u
)
=
2
(
−
(
x
−
c
(
u
)
)
⊤
c
˙
(
u
)
−
r
(
u
)
r
˙
(
u
)
)
=
0
{\displaystyle f_{u}({\mathbf {x} },u)=2{\Big (}-{\big (}{\mathbf {x} }-{\mathbf {c} }(u){\big )}^{\top }{\dot {\mathbf {c} }}(u)-r(u){\dot {r}}(u){\Big )}=0}
of the canal surface above is for any value of
u
{\displaystyle u}
the equation of a plane, which is orthogonal to the tangent
c
˙
(
u
)
{\displaystyle {\dot {\mathbf {c} }}(u)}
of the directrix. Hence the envelope is a collection of circles.
This property is the key for a parametric representation of the canal surface. The center of the circle (for parameter
u
{\displaystyle u}
) has the distance
d
:=
r
r
˙
‖
c
˙
‖
<
r
{\displaystyle d:={\frac {r{\dot {r}}}{\|{\dot {\mathbf {c} }}\|}}<r}
(see condition above)
from the center of the corresponding sphere and its radius is
r
2
−
d
2
{\displaystyle {\sqrt {r^{2}-d^{2}}}}
. Hence
-
x
=
x
(
u
,
v
)
:=
c
(
u
)
−
r
(
u
)
r
˙
(
u
)
‖
c
˙
(
u
)
‖
2
c
˙
(
u
)
+
r
(
u
)
1
−
r
˙
(
u
)
2
‖
c
˙
(
u
)
‖
2
(
e
1
(
u
)
cos
(
v
)
+
e
2
(
u
)
sin
(
v
)
)
,
{\displaystyle {\mathbf {x} }={\mathbf {x} }(u,v):={\mathbf {c} }(u)-{\frac {r(u){\dot {r}}(u)}{\|{\dot {\mathbf {c} }}(u)\|^{2}}}{\dot {\mathbf {c} }}(u)+r(u){\sqrt {1-{\frac {{\dot {r}}(u)^{2}}{\|{\dot {\mathbf {c} }}(u)\|^{2}}}}}{\big (}{\mathbf {e} }_{1}(u)\cos(v)+{\mathbf {e} }_{2}(u)\sin(v){\big )},}
-
x
=
x
(
u
,
v
)
:=
c
(
u
)
−
r
(
u
)
r
˙
(
u
)
‖
c
˙
(
u
)
‖
2
c
˙
(
u
)
+
r
(
u
)
1
−
r
˙
(
u
)
2
‖
c
˙
(
u
)
‖
2
(
e
1
(
u
)
cos
(
v
)
+
e
2
(
u
)
sin
(
v
)
)
,
{\displaystyle {\mathbf {x} }={\mathbf {x} }(u,v):={\mathbf {c} }(u)-{\frac {r(u){\dot {r}}(u)}{\|{\dot {\mathbf {c} }}(u)\|^{2}}}{\dot {\mathbf {c} }}(u)+r(u){\sqrt {1-{\frac {{\dot {r}}(u)^{2}}{\|{\dot {\mathbf {c} }}(u)\|^{2}}}}}{\big (}{\mathbf {e} }_{1}(u)\cos(v)+{\mathbf {e} }_{2}(u)\sin(v){\big )},}
where the vectors
e
1
,
e
2
{\displaystyle {\mathbf {e} }_{1},{\mathbf {e} }_{2}}
and the tangent vector
c
˙
/
‖
c
˙
‖
{\displaystyle {\dot {\mathbf {c} }}/\|{\dot {\mathbf {c} }}\|}
form an orthonormal basis, is a parametric representation of the canal surface.[2]
For
r
˙
=
0
{\displaystyle {\dot {r}}=0}
one gets the parametric representation of a pipe surface:
-
x
=
x
(
u
,
v
)
:=
c
(
u
)
+
r
(
e
1
(
u
)
cos
(
v
)
+
e
2
(
u
)
sin
(
v
)
)
.
{\displaystyle {\mathbf {x} }={\mathbf {x} }(u,v):={\mathbf {c} }(u)+r{\big (}{\mathbf {e} }_{1}(u)\cos(v)+{\mathbf {e} }_{2}(u)\sin(v){\big )}.}
-
x
=
x
(
u
,
v
)
:=
c
(
u
)
+
r
(
e
1
(
u
)
cos
(
v
)
+
e
2
(
u
)
sin
(
v
)
)
.
{\displaystyle {\mathbf {x} }={\mathbf {x} }(u,v):={\mathbf {c} }(u)+r{\big (}{\mathbf {e} }_{1}(u)\cos(v)+{\mathbf {e} }_{2}(u)\sin(v){\big )}.}


Examples
- a) The first picture shows a canal surface with
- the helix
(
cos
(
u
)
,
sin
(
u
)
,
0.25
u
)
,
u
∈
[
0
,
4
]
{\displaystyle (\cos(u),\sin(u),0.25u),u\in [0,4]}
as directrix and
- the radius function
r
(
u
)
:=
0.2
+
0.8
u
/
2
π
{\displaystyle r(u):=0.2+0.8u/2\pi }
.
- The choice for
e
1
,
e
2
{\displaystyle {\mathbf {e} }_{1},{\mathbf {e} }_{2}}
is the following:
-
e
1
:=
(
b
˙
,
−
a
˙
,
0
)
/
‖
⋯
‖
,
e
2
:=
(
e
1
×
c
˙
)
/
‖
⋯
‖
{\displaystyle {\mathbf {e} }_{1}:=({\dot {b}},-{\dot {a}},0)/\|\cdots \|,\ {\mathbf {e} }_{2}:=({\mathbf {e} }_{1}\times {\dot {\mathbf {c} }})/\|\cdots \|}
.
- the helix
(
cos
(
u
)
,
sin
(
u
)
,
0.25
u
)
,
u
∈
[
0
,
4
]
{\displaystyle (\cos(u),\sin(u),0.25u),u\in [0,4]}
- b) For the second picture the radius is constant:
r
(
u
)
:=
0.2
{\displaystyle r(u):=0.2}
, i. e. the canal surface is a pipe surface.
- c) For the 3. picture the pipe surface b) has parameter
u
∈
[
0
,
7.5
]
{\displaystyle u\in [0,7.5]}
.
- d) The 4. picture shows a pipe knot. Its directrix is a curve on a torus
- e) The 5. picture shows a Dupin cyclide (canal surface).
See also
References
Further reading
- Hilbert, David; Cohn-Vossen, Stephan (1952). Geometry and the Imagination (2nd ed.). Chelsea. p. 219. ISBN 0-8284-1087-9.
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