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Seward Township, Kosciusko County, Indiana

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Seward Township
Coordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°W / 41.10806; -85.94611
CountryUnited States
StateIndiana
CountyKosciusko
Government
  TypeIndiana township
Area
  Total
36.27 sq mi (93.9 km2)
  Land34.98 sq mi (90.6 km2)
  Water1.3 sq mi (3.4 km2)
Elevation876 ft (267 m)
Population
  Total
2,280
  Density73.4/sq mi (28.3/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
FIPS code18-68796[3]
GNIS feature ID453840

Seward Township is one of seventeen townships in Kosciusko County, Indiana, United States. As of the 2020 census, its population was 2,280 (down from 2,567 at 2010[4]) and it contained 1,357 housing units.

Seward Township was organized in 1859.[5]

Geography

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km2), of which 34.98 square miles (90.6 km2) (or 96.44%) is land and 1.3 square miles (3.4 km2) (or 3.58%) is water.[4]

Cities and towns

References